I was working in a SQL Server 2005 setup case which failed while starting SQL Service with error:
SQL Server Setup could not connect to the database service for server configuration. The error was: [Microsoft][SQL Native Client][SQL Server]Login failed for user 'sa'. Refer to server error logs and setup logs for more information.
Then I reviewed the SQL Server error log and noted that
DateTime Logon Error: 18456, Severity: 14, State: 10
DateTime Logon Login failed for user 'sa'.
As per http://support.microsoft.com/kb/925744 State 10 corresponds to PASSWORD POLICY CHECK failure. The box I was working was in a workgroup. So we went ahead and used trace flag 4606 to byepass password policy check.
How to do that?
Create a reg key by name “SQLArg3” of type REG_SZ in the registry location
HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Microsoft SQL Server\<Instance ID Created by the install>\MSSQLServer\Parameters
and add the value “-T4606”
Note: SQLArg3 should be replaced with a value higher than existing keys. So if you already have SQLArg0, SQLArg1, SQLArg2, SQLArg3 then add the value above with SQLArg4
Read more: Sakthi's SQL Server Channel
SQL Server Setup could not connect to the database service for server configuration. The error was: [Microsoft][SQL Native Client][SQL Server]Login failed for user 'sa'. Refer to server error logs and setup logs for more information.
Then I reviewed the SQL Server error log and noted that
DateTime Logon Error: 18456, Severity: 14, State: 10
DateTime Logon Login failed for user 'sa'.
As per http://support.microsoft.com/kb/925744 State 10 corresponds to PASSWORD POLICY CHECK failure. The box I was working was in a workgroup. So we went ahead and used trace flag 4606 to byepass password policy check.
How to do that?
Create a reg key by name “SQLArg3” of type REG_SZ in the registry location
HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Microsoft SQL Server\<Instance ID Created by the install>\MSSQLServer\Parameters
and add the value “-T4606”
Note: SQLArg3 should be replaced with a value higher than existing keys. So if you already have SQLArg0, SQLArg1, SQLArg2, SQLArg3 then add the value above with SQLArg4
Read more: Sakthi's SQL Server Channel